Himachal Pradesh TET-Medical-June-2023 Solved Paper
हिमाचल प्रदेश शिक्षक पात्रता परीक्षा
Welcome to our exclusive complete collections of Himachal Pradesh-"Medical" Teacher Eligibilty Test (HP-TET-Medical) old fully solved question papers. Here we are sharing Himachal Pradesh TET Medical-June-2023 fully Solved Paper. All questions are of multiple choice type(MCQs).These questions (MCQs) are very helpful for those candidates or aspirants who are preparing for the various government, non government exams as well as in interview.These multiple choice questions(MCQs) are helpful in preparing various competitive exams like TET, CTET, Clerk, Patwari, Naib tehsildhar, UPSC, PSC, HPPSC, JBT, LT, TGT, PGT, KVS, VS, NET, SLET, PET, DM and SET.
हिमाचल प्रदेश शिक्षक पात्रता परीक्षा (HPTET-Medical) परीक्षा का आयोजन हिमाचल प्रदेश बोर्ड ऑफ स्कूल एजुकेशन (HPBOSE)धर्मशाला द्वारा -June-2023 में किया। हिमाचल प्रदेश शिक्षक पात्रता परीक्षा-June-2023 का प्रश्नपत्र उत्तर कुंजी सहित यहाँ पर उपलब्ध है हम यंहा पर हिमाचल प्रदेश
Himachal Pradesh TET-Medical-June-2023 Solved Paper with answer keys
Conducted By : Himachal Pradesh Board of School Education (HPBOSE)
Examination Date : 26-09-2023
Total Marks : 150
Total Question : 150
Psychology and Pedagogy : 30 Question
Botany and Zoology : 60 Question
Chemistry : 30 Question
General Awareness and EVS : 30 Question
Himachal Pradesh-TET-Medical-JUNE-2023 Fully solved paper with answer keys conducted by Himachal Pradesh Board of school education on 26-09-2023
Himachal Pradesh TET-Medical-june-2023 Solved Paper | SET-6
Question : 51-60
Website : https://hpallexam.blogspot.com
Name of the following compound is : (CH3)3 - C – CH = CH2
Hex-1-ene
3,3-Dimethyl but-1-ene
2,2 Dimethyl 3 buteneWebsite : https://hpallexam.blogspot.com
A solution has 320g water and 40g NaCl dissolved in it, then the mass percent concentration of NaCl is :
11.1%
10.5%
20.2% Website : https://hpallexam.blogspot.com
When SO2 is dissolved in water , the acid that is formed is :
Sulphuric Acid
Pyrosulphuric Acid
Sulphurous AcidWebsite : https://hpallexam.blogspot.com
number of electrons present in 10 gram of H2 O are :
(6.023 x 1023) /6
(6.023 x 1025) /6
(6.023 x 1022) /6Website : https://hpallexam.blogspot.com
Website : https://hpallexam.blogspot.com
Complete the reaction by selecting right option CH3CH2OH 443K⇒ Conc. H2SO4 ……………..
CH3CH2SO3H + H2O
CH2 = CH2 +H2O
CH3CH2 - O – CH2 - CH 3Website : https://hpallexam.blogspot.com
Website : https://hpallexam.blogspot.com
Website : https://hpallexam.blogspot.com
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