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HP-TGT-NM-COMMISSION-2014 Part-1

Himachal Pradesh TGT Non-Medical Commission-2014 (Post Code-359) Solved Paper | SET-1
Himachal Pradesh-TGT Non-Medical Commission-Exam-2014 (Post Code-359) Solved Paper

Himachal Pradesh-TGT Non-Medical Commission-Exam-2014 (Post Code-359) Solved Paper

Himachal Pradesh Non-Medical Commission- Exam-2014 (Post Code-359) Solved Paper. Himachal Pradesh Staff Selection Commission (HPSSC) conducted HP -Non-Medical Commission- Exam-2014 (Post Code-359) on 04.03. 2014. HP-Medical Commission- Exam-2014 (Post Code-359) solved Paper available here With Official Answer Key.Total no of questions are 200 and total marks are 200. Time allotted for exam 2 hour(120 Minutes). All questions are of multiple choice type(MCQs).These questions (MCQs) are very helpful for those candidates or aspirants who are preparing for the various government, non government exams as well as in interview.These multiple choice questions(MCQs) are helpful in preparing various competitive exams like HPSAS, HPAS,TET, Police SI. Police constable, CTET, Clerk, Patwari, UPSC, Naib tehsildhar, PSC, HPPSC, JBT, LT, TGT, PGT, KVS, VS, NET, SLET, PET, DM and SET.

Himachal Pradesh-TGT Non-Medical Commission-Exam-2014 (Post Code-359) Solved Paper

Examination  :   Himachal Pradesh-NonMedical-Commission-2014
Conducted By :   Himachal Pradesh Staff Selection Commission (HPSSC)
Examination Date :  04.03.2014
Total Marks :   200
Total Question :   200
Paper Series :   SET-B
Post Code :   (C-216) -359
TIME :   2 Hours

Himachal Pradesh-TGT Non-Medical Commission-Exam-2014 (Post Code-359) Solved Paper with answer keys


Himachal Pradesh TGT Non-Medical Commission-2014 (Post Code-359) Solved Paper | SET-1
Question : 1-10


Question : 1

The main active constituents of tea and coffee is

[A].   Nocotine
[B].   Chlorophyll
[C].   Caffeine
[D].   Aspirin



HP-TGT Non-Medical-Commission-2014 Solved Paper
By : HP-All-Exam Master
https://hpallexam.blogspot.com



Question : 2

The items amenable to detection by soft X-rays are

[A].   Contrabands
[B].   Lead in bullets
[C].   Narcotics
[D].   Genuine coins from counterfeit coins



HP-TGT Non-Medical-Commission-2014 Solved Paper
By : HP-All-Exam Master
https://hpallexam.blogspot.com



Question : 3

When a primary amine reacts with CHCl3 in the presence of ethanolic KOH, then the product is

[A].   an isocyanide
[B].   an aldehyde
[C].   a cyanide
[D].   an alcohol



HP-TGT Non-Medical-Commission-2014 Solved Paper
By : HP-All-Exam Master
https://hpallexam.blogspot.com



Question : 4

Which of the following compounds is not Chiral ?

[A].   1-chloro-2-methyl pentane
[B].   2-chloropentane
[C].   1-chloropentane
[D].   3-chloro-2-methyl pentane



HP-TGT Non-Medical-Commission-2014 Solved Paper
By : HP-All-Exam Master
https://hpallexam.blogspot.com



Question : 5

The reaction CH3Br + AgF → CH3F + AgBr is Called

[A].   Swart’s reaction
[B].   Finkelstein reaction
[C].   Gattermann’s reaction
[D].   Perkin’s reaction



HP-TGT Non-Medical-Commission-2014 Solved Paper
By : HP-All-Exam Master
https://hpallexam.blogspot.com



Question : 6

Which enzyme converts glucose into ethanol and CO2 ?

[A].   Diastage
[B].   Maltase
[C].   Invertase
[D].   Zymase



HP-TGT Non-Medical-Commission-2014 Solved Paper
By : HP-All-Exam Master
https://hpallexam.blogspot.com



Question : 7

If 20 g of CaCO3 is treated with 20 g of Hcl, how many gram of CO2 can be obtained according to the following reaction ?
CaCO3 + 2HCl (aq → CaCl2 (aq + H2O (l)+ CO2 (g)

[A].   8.80 g
[B].   27.4 g
[C].   4.20 g
[D].   13.7 g



HP-TGT Non-Medical-Commission-2014 Solved Paper
By : HP-All-Exam Master
https://hpallexam.blogspot.com



Question : 8

Out of the first 80 elements the number of elements having 3d orbital is

[A].   10
[B].   30
[C].   60
[D].   20



HP-TGT Non-Medical-Commission-2014 Solved Paper
By : HP-All-Exam Master
https://hpallexam.blogspot.com



Question : 9

The termthat corrects for the attractive forces present in a real gas in the Vander Waals equation is

[A].   nb
[B].   an2/v2
[C].   -an2/v2
[D].   -nb



HP-TGT Non-Medical-Commission-2014 Solved Paper
By : HP-All-Exam Master
https://hpallexam.blogspot.com



Question : 10

Which of the following is correct quadratic form of Istwald’s dilution law equation ?

[A].   α2 + αK + K = 0
[B].   α2 - αK + K = 0
[C].   α2 - αK - K = 0
[D].   α2 + αK - K = 0



HP-TGT Non-Medical-Commission-2014 Solved Paper
By : HP-All-Exam Master
https://hpallexam.blogspot.com





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